(2^2)^x*2^(3x)=32

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Solution for (2^2)^x*2^(3x)=32 equation: 



(2^2)^x*2^(3x)=32

We move all terms to the left:

(2^2)^x*2^(3x)-(32)=0

Wy multiply elements

4x^5-32=0

We do not support expression: x^5

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